Knowing the fact that LCM of 2 or more numbers, is the
smallest number which could e found, so that this one to be divided by each number from
the given set of numbers, we have to factor each of the given numbers, into it's prime
factors.
Let's factor
c+3=1*(c+3).
Now, let's factor c^2+4c+3. Noticing that the
expression c^2+4c+3 is a second degree polynomial, we'll write it's equation and find
it's roots in order to write the polynomial as a product of linear
factors.
c^2+4c+3=0
c1 =
[-4+sqrt(16-12)]/2
c1 =
(-4+2)/2
c1 = -1
c2 =
(-4-2)/2
c2 = -3
So, the
polynomial c^2+4c+3, could be writtenas:
c^2+4c+3 =
(c-(-1))(c-(-3)) = (c+1)(c+3)
So, the prime factors
of c^2+4c+3 are (c+1) and (c+3).
It is obvious that the
number c^2+4c+3 could be divided by (c+3) and the number (c+3) could be divided by
itself.
So, the LCM of the
numbers c^2+4c+3 and c+3 is c+3.
No comments:
Post a Comment