It is an elementary limit.
Let's see how could it be solved:
Lim arctg(x)/(x+1) = arctg lim(x)/(x+1)
We'll write the ratio x/(x+1) = (x+1-1)/(x+1) = (x+1)/(x+1) + (-1)/(x+1)
lim(x)/(x+1) = lim[(x+1)/(x+1) + (-1)/(x+1)]
lim[(x+1)/(x+1) + (-1)/(x+1)] = lim[1 + (-1)/(x+1)]
lim{[1 + (-1)/(x+1)]^[-(x+1)]}^[(-1)/(x+1)]
But, lim{[1 + (-1)/(x+1)]^[-(x+1)] = e, so:
lim{[1 + (-1)/(x+1)]^[-(x+1)]}^[(-1)/(x+1)] = e^lim[(-1)/(x+1)], where lim[(-1)/(x+1)] =-1/inf. = 0
arctg lim(x)/(x+1) = arctg e^0 =arctg 1 = pi/4
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