p(x)= x^3-x^2+2x-8
(x-2) is a factor??
Solution:
To determine if (x-2) is one of the function's solution, we use the factor theorem. If (x-2) is a factor, then the remainder of dividing p(x) by (x=2) IS ZERO.
Using synthetic division:
2 l 1 -1 2 -8
2 2 8
--------------------------
1 1 4 0
The remainder is 0, then (x-2) is a factor of p(x)
Then the statement is true and the other factor is X^2+x+4
Then P(x) = (x-2)(x^2+x+4)
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