Which is the value of the sum x1+x2+x3, if x1, x2, x3 are the solutions of the equation x^3-3x^2+2x=0?

We'll use the first Viete's relation, in order to calculate the sum x1 + x2 + x3.

For a polynomial  ax^3+bx^2+cx+d=0,

x1 + x2 + x3 = -b/a

We'll identify the coefficients from the given polynomial:

a = 1

b = -3

c = 2

d = 0

So, calculating the sum, we'll get:

x1 + x2 + x3 = -b/a = - (-3/1)

x1 + x2 + x3 = 3