First, we'll choose 2 numbers: x1<x2.
Based on the rule of an increasing function, we'll have to prove that f(x1)<f(x2), also.
Supposing that is given the fact that f'(x)>0 and from here, we'll conclude that f is differentiable on the interval [x1, x2].
Now, we'll apply the Mean Value Theorem, which states that:
f(x2)-f(x1)=f'(c)(x2-x1)
From enunciation, we have that f'(c)>0 and, because we've choosen that x2>x1, we'll havex2-x1>0.
So, the product f'(c)(x2-x1)>0.
But the product f'(c)(x2-x1) = f(x2)-f(x1)
From here, we conclude that f(x2)-f(x1)>0
That means that f(x2)>f(x1), which means that f(x) is an increasing function.
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