Sunday, May 4, 2014

Evaluate the limit (3x+5)/(x^2+1), x->+infinity?

In order to calculate the limit of a rational function, when x tends to +inf., we'll divide both, numerator and denominator, by the highest power of x, which in this case is x^2.


We'll have:


lim (3x+5)/(x^2+1) = lim (3x+5)/lim (x^2+1)


lim (3x+5)/lim (x^2+1) = lim x^2*(3/x + 5/x^2)/lim x^2*(1 + 1/x^2)


After reducing similar terms, we'll get:


lim (3x+5)/lim (x^2+1) = (0+0)/(1+0)=0

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