I believe we are talking about a 6 sided cubical dice marked with numbers 1 to 6 on the sides. In this dice the probability of getting any particular number on roll of a dice is 1/6>
Therefore the probability of getting a 6 in any one roll is 1/6.
Therefore the probability of getting a 6 in first roll is 1/6.
The probability of getting a six in first two rolls is:
= (Probability of getting a 6 in first roll)x(Probability of getting a 6 in second roll)
= (1/6)x(1/6) = (1/6)^2
Similarly the probability of getting a 6 in first 4 rolls = (1/6)^4
= 1/1296 = 0.0007716
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