This is a trigonometric elementary equation.
We'll move the free term to the right side:
tg x = 1
The function tangent is positive in the first and the third quadrants.
Now, let's find out for what values of angles, the tangent has the value 1.
x = arctg 1 + k*pi
x = pi/4 + k*pi
If k = 0, x = pi/4 and it is an angle located in the first quadrant.
If k = 0, x = pi/4 + pi and it is an angle located in the third quadrant.
So, over the interval (0, 2pi), the equation will have only 2 solutions, namely: {pi/4}U{pi + pi/4}.
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